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General solution of differential equation : $(1+y^2)dx =(\tan^{-1}y -x)dy$

$(a)\;x= \tan ^{-1} x+1+ce^{\tan ^{-1} x} \\ (b)\;y= \tan ^{-1} x+1+ce^{\tan ^{-1} x} \\ (c)\;x= \tan ^{-1} -1+ce^{\tan ^{-1} x} \\ (d)\;y= \tan ^{-1} x-1+ce^{\tan ^{-1} x} $

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