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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
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Find the equation of a line which is equidistant from the line $x=\large\frac{15}{2}$ and $x=\large\frac{1}{2}$?

$(a)\;x=4\qquad(b)\;x=5\qquad(c)\;x=3\qquad(d)\;x=2$

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1 Answer

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The line will be exactly in between the two line $x=\large\frac{15}{2}$ and $x=\large\frac{1}{2}$
So the line should be at the mid of these two lines hence the equation of line will be
$x=\large\frac{\Large\frac{15}{2}+\frac{1}{2}}{2}$
$x=4$
This is the required equation.
Hence (a) is the correct answer.
answered Feb 4, 2014 by sreemathi.v
 

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