$(a)\;x=4\qquad(b)\;x=5\qquad(c)\;x=3\qquad(d)\;x=2$

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The line will be exactly in between the two line $x=\large\frac{15}{2}$ and $x=\large\frac{1}{2}$

So the line should be at the mid of these two lines hence the equation of line will be

$x=\large\frac{\Large\frac{15}{2}+\frac{1}{2}}{2}$

$x=4$

This is the required equation.

Hence (a) is the correct answer.

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