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Coordinate Geometry
Find the equations of the bisectors of the angle between the co-ordinate axes?
$(a)\;y=\pm x\qquad(b)\;y=\pm 2x\qquad(c)\;y=\pm 3x\qquad(d)\;y=\pm 4x$
jeemain
math
class11
coordinate-geometry
straight-lines
equations-of-a-line
ch10
q7
easy
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asked
Feb 4, 2014
by
sreemathi.v
retagged
Sep 18, 2014
by
sharmaaparna1
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1 Answer
Equation of bisector will be $y=mx$
$m=\tan 45^{\large\circ}=1$
Or $m=\tan 135^{\large\circ}=-1$
Hence equation of bisectors will be
$y=\pm x$
(i.e) $y=x$ &$y=-x$
Hence (a) is the correct answer.
answered
Feb 4, 2014
by
sreemathi.v
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