logo

Ask Questions, Get Answers

X
 
Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class11  >>  Coordinate Geometry

Find the equation of straight line passing through $(at_1,\large\frac{a}{t_1})$ & $(at_2,\large\frac{a}{t_2})$?

$\begin{array}{1 1}(a)\;t_1t_2y+x=a(t_2+t_1)\\(b)\;t_1t_2x+y=a(t_2+t_1)\\(c)\;2t_1t_2y+x=a(t_2+t_1)\\(d)\;t_1t_2y+x=2a(t_2+t_1)\end{array}$

1 Answer

Equation of line will be
$(y-\large\frac{a}{t_1})=\frac{\Large\frac{a}{t_2}-\frac{a}{t_1}}{a(t_2-t_1)}$$(x-at_1)$
$(y-\large\frac{a}{t_1})=\frac{a(t_1-t_2)(x-at_1)}{t_2t_1\times a(t_2-t_1)}$
$(y-\large\frac{a}{t_1})=\frac{-1(x-at_1)}{t_1t_2}$
$(y-\large\frac{a}{t_1})=\large\frac{a}{t_2}-\frac{x}{t_1t_2}$
$y+\large\frac{x}{t_1t_2}=\frac{a(t_2+t_1)}{t_2t_1}$
$t_1t_2y+x=a(t_2+t_1)$
This equation is also known as parametric equation of line.
Hence (a) is the correct answer.
answered Feb 4, 2014 by sreemathi.v
 

Related questions

...