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The image of the point (4,-3) with respect to the line $y=x$ is :


1 Answer

The line $y=x$ passes through (0,0) and $y=x$ line has the same distance from the point (4,-3) and the mirror image point hence (0,0) is the mid-point of the points (4,-3) and mirror image points.(Mirror image point will lie on perpedicular (i.e) $y=-x$)
$\therefore x_1=-4,y_1=3$
That is (-4,3)
Hence (a) is the correct answer.
answered Feb 4, 2014 by sreemathi.v

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