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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
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The vertices of a triangle are $A(10,4),B(-4,9)$ and $C(-2,-1)$.Find the equation of the altitude through A?

$\begin{array}{1 1}(a)\;x-5y+12=0\\(b)\;x-5y+10=0\\(c)\;x+5y+12=0\\(d)\;5x-5y+12=0\end{array}$

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1 Answer

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Slope of BC=$\large\frac{-1-9}{-2+4}$
$\Rightarrow \large\frac{-10}{2}$$=-5$
$\therefore$ Slope of altitude AD=$\large\frac{-1}{-5}=\frac{1}{5}$
Hence equation of altitude AD with slope $\large\frac{1}{5}$ is
$(y-4)=\large\frac{1}{5}$$(x-10)$
$x-5y+10=0$
Hence (b) is the correct answer.
answered Feb 4, 2014 by sreemathi.v
 

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