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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
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Find the equation of the line through (1,2) so that the segment of line intercepted between the axes is bisected at this point?

$\begin{array}{1 1}(a)\;y+2x=5\\(b)\;y+2x=4\\(c)\;y+3x=7\\(d)\;y+2x=9\end{array}$

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1 Answer

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(1,2) is the mid point of $(0,b)$ & $(a,0)$
Hence $\large\frac{a+0}{2}$$=1$
$a=2$
$\large\frac{b+0}{2}$$=2$
$b=4$
Hence equation of line is
$(y-4)=\large\frac{0-4}{2-0}$$(x-0)$
$y-4=-2(x)$
$y+2x=4$
Hence (b) is the correct answer.
answered Feb 4, 2014 by sreemathi.v
 

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