Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
0 votes

$A(1,2)$ & $B(7,6)$ are the two opposite points of straight line (i.e) these two points are on opposite side of a straight line then find a equation of straight line which is equidistant from these two points and also AB is perpendicular to the straight line.

$\begin{array}{1 1}(a)\;2y+3x=20\\(b)\;3y+2x=20\\(c)\;y+3x=10\\(d)\;2y+x=20\end{array}$

Can you answer this question?

1 Answer

0 votes
Mid-point of the points $A(1,2)$ & $B(7,6)$ is $C(x,y)$
Hence straight line passes through (4,4)
BC is perpendicular to straight line.Hence slope of $BC=\large\frac{6-4}{7-4}=\frac{2}{3}$
So the slope of straight line will be $-\large\frac{3}{2}$
Hence equation of straight line is $(y-4)=-\large\frac{3}{2}$$(x-4)$
Hence (a) is the correct answer.
answered Feb 4, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App