(1-\(P_1\))\(P_2\)=[(1-P(\(E_1\))\(E_2\)]

=probability of simultanious occurance of\(E_2\)and non occurance of\(E_1\)

=probability only occurance of\(E_2\)

1-(1-\(P_1\))(1-\(P_2\))=1-\(P(\bar{E}_1)\) \(P(\bar{E}_2)\)

=probability eather \(E_1\) or\(E_2\)occurance

\(P_1\)+\(P_2\)-2\(P_1\)\(P_2\)=\(P(E_1)\)+ \(P(E_2)\)-\(P(E_1(\cap)E_2)\)

probability exactly one of the event \(E_1\) or\(E_2\)occurance