Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A certain laser transition emits $6.37\times10^{15}$ quants per second per square meter. Calculate the power out put in joule per square metre per second. Given $\lambda$ = 632.8 nm.


Can you answer this question?

1 Answer

0 votes
Energy falling per square meter per second = No. of quanta falling/$m^2/sec\times$ energy of one quanta
$= 6.37\times10^{15}\times\large\frac{hc}{\lambda}$
$=2\times10^{-3} J/m^2/sec$
Hence answer is (a)
answered Feb 4, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App