General solution of differential equation: $(x+1) \large\frac{dy}{dx}$$-y = (x+1)^2$

Question

$(a)\;\frac{y}{x+1}=(x+1)+y+c \\ (b)\;\frac{y}{x+1}=x+c \\ (c)\;\frac{x}{x+1}=y+c \\ (d)\;\frac{y}{x}=(x+1)+c $