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Three dice are thrown at the same time.Find the probability of getting three two's,if it is known that the sum of the numbers on the dice was six.
cbse
class12
ch13
q14
p273
short-answer
exemplar
sec-a
easy
math
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asked
Jan 8, 2013
by
sreemathi.v
edited
Apr 8, 2014
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Three die are thrown simultaneously
There are 216 elements in the total sample space
Let us define an element A assum of the numbers on the dice is 6
A=\((2\;2\;2)(2\;1\;3)(2\;3\;1)(1\;3\;2)(1\;2\;3)(1\;1\;4)(4\;1\;1)(1\;4\;1)(3\;1\;2)(3\;2\;1\;)\)
B=getting a number 3 in all 3 diesa=(\(2\;2\;2)\)
Since it is given that the event A has alreay occured ie the sum of the numberss on each die is 6
We have 10 cases out of which only one(\(2\;2\;2)\) is faverable to us
P(B)=\(\frac{1}{10}\)
answered
Feb 26, 2013
by
poojasapani_1
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