Browse Questions

Three dice are thrown at the same time.Find the probability of getting three two's,if it is known that the sum of the numbers on the dice was six.

Toolbox:
• Three die are thrown simultaneously
• There are 216 elements in the total sample space
• Let us define an element A assum of the numbers on the dice is 6
• A=$(2\;2\;2)(2\;1\;3)(2\;3\;1)(1\;3\;2)(1\;2\;3)(1\;1\;4)(4\;1\;1)(1\;4\;1)(3\;1\;2)(3\;2\;1\;)$
• B=getting a number 3 in all 3 diesa=($2\;2\;2)$
Since it is given that the event A has alreay occured ie the sum of the numberss on each die is 6
We have 10 cases out of which only one($2\;2\;2)$ is faverable to us
P(B)=$\frac{1}{10}$