logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The electric field in a region is given by $\;\overrightarrow{E}=\large\frac{\in_{0} x \hat{i}}{l}\;.$ Find the charge contained inside a cubical volume bounded by the surfaces $\;x=0 , x=a , y=0 , y=a , z=0 , z=a $ where $a= 10^{-2} m$ and $l= 2 \times 10^{-2}\; m$

$(a)\;22\times10^{-12}\;C\qquad(b)\;0.22\times10^{-12}\;C\qquad(c)\;2.2\times10^{-12}\;C\qquad(d)\;4.4\times10^{-12}\;C$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : (c) $\;2.2\times10^{-12}\;C$
Explanation : Electric flux through five surfaces is zero . The electric flux through on surface x=a plane is :
$\phi=\large\frac{\in_{0}\;a}{l}\;a^2=\large\frac{Q}{\in_{0}}$
$Q=\large\frac{\in_{0}\;a^3\;\in_{0}}{l}$
$Q=\large\frac{5\times10^3\times10^{-6}\times8.86\times10^{-12}}{2\times10^{-2}}$
$Q=2.2\times10^{-12}\;.$

 

answered Feb 5, 2014 by yamini.v
edited Aug 21, 2014 by thagee.vedartham
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...