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Electric potential has the dimensions of

$(a)\;[M L T^{-3} A^{-1}]\qquad(b)\;[M L^{3} T^{-3} A^{-1}]\qquad(c)\;[M L^{2} T^{-3} A^{-1}]\qquad(d)\;None\;of\;these$

1 Answer

Answer : (c) $\;[M L^2 T^{-3} A^{-1}]$
Explanation :
$V = \large\frac{P .E}{q}=\large\frac{k\;g\;m\;m}{S^2\;A\;S}$
$=k\;g\;m^2\;S^{-3}\;A^{-1}$

 

answered Feb 5, 2014 by yamini.v
edited Aug 13, 2014 by thagee.vedartham
 

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