$(a)\;600\;m/s\qquad(b)\;600\;cm/s\qquad(c)\;60\;m/s \qquad(d)\;None\;of\;these$

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Answer : (a) $\;600\;m/s$

Explanation :

Initial P . E=$\;\large\frac{9\times10^{9}\times(2\times10^{-4})^2}{0.1}$

$=9\times10^{9}\times10^{1}\times4\times10^{-8}$

$P .E_{i} =36\times10^2\;J$

Final P . E : $P . E_{f} =0$

Using conservation of momentum and energy

$2\;\large\frac{1}{2}\;mv^2=36\times10^2$

$10^{-2}\times v^2=36\times10^2$

$v=6\times10^2\;m/s\;.$

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