Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Two identical particles , each having a charge of $\;2\times10^{-4}\;C\;$ and mass 10g are kept at a separation of 10 cm and released . What would be the speeds of the particles when the separation becomes large ?

$(a)\;600\;m/s\qquad(b)\;600\;cm/s\qquad(c)\;60\;m/s \qquad(d)\;None\;of\;these$

Can you answer this question?

1 Answer

0 votes
Answer : (a) $\;600\;m/s$
Explanation :
Initial P . E=$\;\large\frac{9\times10^{9}\times(2\times10^{-4})^2}{0.1}$
$P .E_{i} =36\times10^2\;J$
Final P . E : $P . E_{f} =0$
Using conservation of momentum and energy
$10^{-2}\times v^2=36\times10^2$
answered Feb 5, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App