Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
0 votes

An oxide of nitrogen at NTP has a density equal to another oxide of Nitrogen at $12^{\circ}$. If we consider pressure conditions to be the same, what are the two oxides involved?

(A) $NO, NO_2$ (B) $N_2O, NO_2$ (C) $NO, N_2O$ (D) $NO_2, NO$
Can you answer this question?

1 Answer

0 votes
For any ideal gas, density $\rho = \large\frac{PM}{RT}$
So, for densities to be equal under similar conditions of pressure, $\large\frac{M}{T}$ needs to be the same.
For $N_2O$ and $NO_2, \; \large\frac{44}{273} $$= \large\frac{46}{273+12}$
Hence this is the correct answer. (We can verify the values of $\large\frac{M}{T}$ for the other combinations and we'll see that they are not the same).
answered Feb 5, 2014 by balaji

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App