Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
0 votes

Show that normal to the parabola $y^2=4x$ at the point (1,2) meet it again at some point of parabola, find the point?

$\begin{array}{1 1}(a)\;(9,-6)\\(b)\;(8,-6)\\(c)\;(7,-6)\\(d)\;(9,6)\end{array}$

Can you answer this question?

1 Answer

0 votes
We know normal to the parabola $y^2=4x$ is
$(y-2)=-\large\frac{2}{2\times 1}$$(x-1)$
Hence (9,-6) is another point on the parabola.
Hence (a) is the correct answer.
answered Feb 6, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App