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Show that normal to the parabola $y^2=4x$ at the point (1,2) meet it again at some point of parabola, find the point?

$\begin{array}{1 1}(a)\;(9,-6)\\(b)\;(8,-6)\\(c)\;(7,-6)\\(d)\;(9,6)\end{array}$

1 Answer

We know normal to the parabola $y^2=4x$ is
$(y-2)=-\large\frac{2}{2\times 1}$$(x-1)$
Hence (9,-6) is another point on the parabola.
Hence (a) is the correct answer.
answered Feb 6, 2014 by sreemathi.v

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