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There is an electric field E in x - direction . If the work done on moving a charge of 0.2C through a distance of 2m along a line making an angle $\;60_{0}\;$ with x - axis is 4J . What is value of E

$(a)\;\sqrt{3}\;N/C\qquad(b)\;4\;N/C\qquad(c)\;5\;N/C\qquad(d)\;20\;N/C$

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Answer : (d) $\;20\;N/C$
Explanation : $\;W=\overrightarrow{F} . \overrightarrow{r}\quad\;\overrightarrow{F}=0.2 E \hat{i}$
$\overrightarrow{r}=2 cos \theta \hat{i} + 2 sin \theta \hat{j}$
$=\hat{i} + \sqrt{3} \hat{j}$
$W=0.2 E=4$
$E=20 N/C$
answered Feb 6, 2014 by yamini.v
 

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