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A die is thrown 5 times.Find the probability that an odd number will come up exactly three times.

1 Answer

  • Die is thrown 5 times In a single throw of die
  • $P$(getting odd)$=\large\frac{3}{6}=\large\frac{1}{2}$
  • $p=\large\frac{1}{2},$ $q=1-\large\frac{1}{2}$$=\large\frac{1}{2}$
  • \(X=0\; X=1\; X=2\; X=3\; X=4\; X=5\)
  • X={\(0\;1\;2\;3\;4\;5\)}
  • $P(X=r)=^n C_r p^r q^{n-r}$
Die is thrown $5$ times. $\therefore \:n=5$
$P(X=$odd no comes exactly 3 times) $=P(X=3)$
We know that $P(X=r)=^n C_r p^r q^{n-r}$
answered Feb 27, 2013 by poojasapani_1
edited Apr 7, 2014 by rvidyagovindarajan_1

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