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Two thin wire rings each having radius R are placed at a distance d apart with their axes coinciding . The charges on the two rings are +Q and -Q .The potential difference between the centres of the two rings is


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Answer : (c) $\;2kQ\;(\large\frac{1}{R}-\large\frac{1}{\sqrt{R^2+d^2}})$
Explanation :
Potential at O :
Potential at $\;O_{1}\;:$
answered Feb 6, 2014 by yamini.v

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