Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

A charge particle 'q' is shot towards another charged particle 'Q' which is fixed , with a speed 'v'.It approaches 'Q' upto a closest distance r and then returns . If q were given a speed of '2v' the closest distance of approach would be


Can you answer this question?

1 Answer

0 votes
Answer : (d) $\;\large\frac{r}{4}$
Explanation :
$4 r^{|} = r $
$r^{|} = \large\frac{r}{4}\;.$
answered Feb 6, 2014 by yamini.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App