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A charge particle 'q' is shot towards another charged particle 'Q' which is fixed , with a speed 'v'.It approaches 'Q' upto a closest distance r and then returns . If q were given a speed of '2v' the closest distance of approach would be


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Answer : (d) $\;\large\frac{r}{4}$
Explanation :
$4 r^{|} = r $
$r^{|} = \large\frac{r}{4}\;.$
answered Feb 6, 2014 by yamini.v

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