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# The initial value problem governing the current i following in an RL circuit when a step voltage of magnitude $\in$ is applied to circuit at $t=0$ is given by (R, L, t are constants ) $iR= \large\frac{Ldi}{dt} $$=\in, t > 0, i(0)=0 Determine limiting value of i as t \to \infty (a)\;\frac{\in}{R} \\ (b)\;\frac{2 \in}{R} \\ (c)\;e^{-\frac{RE}{L}} \\ (d)\;e^{\frac{R}{L}} Can you answer this question? ## 1 Answer 0 votes L \large\frac{di}{dt}$$=\in -iR$
$\large\frac{di}{\in -IR}$$=\frac{dt}{L} \large\frac{-1}{R}$$ \log \in iR=\large\frac{t}{L}$
$\log t -iR \bigg]_0^1 =\large\frac{-R}{L}t \bigg]_0^t$