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Find the equation of parabola whose vertex is (4,2) and focus is (6,2)?

$\begin{array}{1 1}(a)\;(y-3)^2=8(k-4)\\(b)\;(y-2)^2=8(k-4)\\(c)\;(y-2)^2=4(k-4)\\(d)\;(y-2)^2=6(k-4)\end{array}$

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