$(a)\;1.2586\times10^{18}photon\qquad(b)\;2.5286\times10^{10}photon\qquad(c)\;2.5286\times10^{18}photon\qquad(d)\;3\times10^{18}photon$

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Power = 15 milliwatts

=0.515 watt=0.515 J/S

$\therefore Energy = 0.515\times2.00$

1.030J obtained in 2 second

E = NhV = $\large\frac{Nhc}{\lambda}$

N = $\large\frac{E\lambda}{hc}$

$=\large\frac{1.030\times488\times10^{-9}}{6.626\times10^{-34}\times3\times10^8}$

$=2.5286\times10^{18}$ photons

Hence anwer is (c)

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