logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Calculate the maximum wavelength in $A^{\large\circ}$ a photon that can initiate the reaction. $Cl_2(g)\rightarrow 2cl(g), \bigtriangleup H = 247$ KJ/mol

$(a)\;385nm\qquad(b)\;585nm\qquad(c)\;185nm\qquad(d)\;485nm$

Can you answer this question?
 
 

1 Answer

0 votes
$\bigtriangleup H(energy)$ = 247KJ/mol (of photon)
$=\large\frac{247\times10^3}{6.02\times10^23}$ j/photon
$=4.103\times10^{-19}$ J/photon
Energy = hv = $\large\frac{hc}{\lambda}$ for a photon
$\therefore \lambda = \large\frac{hc}{\bigtriangleup H}$
$=\large\frac{6.63\times10^{-34} JS\times3\times10^8 m/sec}{4.103\times10^{-19}}$
$=4.85\times10^{-7}m$
=485nm
Hence anwer is (d)
answered Feb 6, 2014 by sharmaaparna1
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...