Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Calculate the maximum wavelength in $A^{\large\circ}$ a photon that can initiate the reaction. $Cl_2(g)\rightarrow 2cl(g), \bigtriangleup H = 247$ KJ/mol


Can you answer this question?

1 Answer

0 votes
$\bigtriangleup H(energy)$ = 247KJ/mol (of photon)
$=\large\frac{247\times10^3}{6.02\times10^23}$ j/photon
$=4.103\times10^{-19}$ J/photon
Energy = hv = $\large\frac{hc}{\lambda}$ for a photon
$\therefore \lambda = \large\frac{hc}{\bigtriangleup H}$
$=\large\frac{6.63\times10^{-34} JS\times3\times10^8 m/sec}{4.103\times10^{-19}}$
Hence anwer is (d)
answered Feb 6, 2014 by sharmaaparna1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App