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Calculate the maximum wavelength in $A^{\large\circ}$ a photon that can initiate the reaction. $Cl_2(g)\rightarrow 2cl(g), \bigtriangleup H = 247$ KJ/mol


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$\bigtriangleup H(energy)$ = 247KJ/mol (of photon)
$=\large\frac{247\times10^3}{6.02\times10^23}$ j/photon
$=4.103\times10^{-19}$ J/photon
Energy = hv = $\large\frac{hc}{\lambda}$ for a photon
$\therefore \lambda = \large\frac{hc}{\bigtriangleup H}$
$=\large\frac{6.63\times10^{-34} JS\times3\times10^8 m/sec}{4.103\times10^{-19}}$
Hence anwer is (d)
answered Feb 6, 2014 by sharmaaparna1

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