$(a)\;91.2\%\qquad(b)\;93.5\%\qquad(c)\;90.5\%\qquad(d)\;92.6\%$

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

Energy associated with $H_2$ molecule corresponding to wavelength.

253.7 nm = $\large\frac{hc}{\lambda}$

$=\large\frac{6.63\times10^{-34}\times3\times10^8}{253.7\times10^{-9}}$

$=7.84\times10^{-19}J$

$=7.84\times10^{-19}\times6.02\times10^{23}$J/mol

$=472\times10^3$J/mol

$\%$ of light energy converted

$=\large\frac{430.53\times10^3}{472\times10^3}\times100$

$=91.2\%$

Hence the answer is (a)

Ask Question

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...