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# What is energy per mol of photons of FM radiowaves with V=102.5 MHZ ?

$(a)\;3.09\times10^{-2}J/mol\qquad(b)\;4.09\times10^{-2}J/mol\qquad(c)\;4.09\times10^2J/mol\qquad(d)\;3.3\times10^{-2}J/mol$

Can you answer this question?

V = 102.5 MHz = $102.5\times10^6 Hz (S^{-1})$
E = $N_{\large\circ}hv/mol$
$E =6.02\times10^{23}\times6.63\times10^{-34}\times102.5\times10^6 J/mol$
$=4.09\times10^{-2} J/mol$
Hence answer is (b)
answered Feb 6, 2014