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What is the ratio of the Rydberg constant for helium to hydrogen atom?

$(a)\;\large\frac{1}{2}\qquad(b)\;\large\frac{1}{4}\qquad(c)\;\large\frac{1}{8}\qquad(d)\;\large\frac{1}{16}$

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$R = -\large\frac{2\pi^2mZ^2e^4}{ch^3}$
$\large\frac{R_{He}}{R_H} = \large\frac{2\times2^2}{1\times1^2}$ = 8
$\large\frac{R_H}{R_{He}} = \large\frac{1}{8}$
Hence answer is (c)
answered Feb 6, 2014 by sharmaaparna1
 

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