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# At a certain distance from a point charge , the field intensity is $\;500 V/m\;$ and the potential is 1500 V . The magnitude of charge is

$(a)\;1 \mu C\qquad(b)\;2 \mu C\qquad(c)\;0.5 \mu C\qquad(d)\;6 \mu C$

Can you answer this question?

Answer : (c) $\;0.5 \mu C$
Explanation :
$\large\frac{k\;q}{r^2}=500$
$\large\frac{k\;q}{r}=1500$
$r = 3m$
Where q is the charge on point charge
$\large\frac{9\times10^{9}\;q}{9}=500$
$q= 0.5 \mu C\;.$

answered Feb 6, 2014 by
edited Aug 13, 2014