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Home  >>  JEEMAIN and NEET  >>  Mathematics  >>  Class12  >>  Differential Equations

Find the solution : $\large\frac{\sqrt x -2}{\sqrt y -1}$$dy =\large\frac{\sqrt y+1}{\sqrt x +2}$$dx$

$(a)\;y= 4-x+c \\ (b)\;y=1+cx \\ (c)\;y=4+cx \\ (d)\;y=1+c(x-4)$

1 Answer

$\large\frac{dy}{y-1} =\frac{dx}{x-4}$
$\log (y-1) =\log (x-4) +\log c$
$y-1=c(x-4)$
$y= 1+ c(x-4)$
Hence d is the correct answer.
answered Feb 6, 2014 by meena.p
 
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