Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
0 votes

Two wires of resistivity $\rho 1$ and $\rho 2$ are connected in series. Equivalent resistivity of the combination is

$\begin {array} {1 1} (A)\;\rho_1+\rho_2 & \quad (B)\;\large\frac{1}{2} (\rho_1+\rho_2) \\ (C)\;2\large\frac{\rho_1\rho_2}{\rho_1+\rho_2} & \quad (D)\;\large\frac{1}{2}\large\frac{\rho_1\rho_2}{\rho_1+\rho_2} \end {array}$


Can you answer this question?

1 Answer

0 votes
$R = R1 + R2$
$ \rho \large\frac{2l}{A} = \rho_1 \large\frac{l}{A} + \rho_2\large\frac{l}{A}$
$ \Rightarrow \large\frac{1}{2} (\rho_1+\rho_2)$
Ans : (B)


answered Feb 8, 2014 by thanvigandhi_1
edited Aug 23, 2014 by thagee.vedartham

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App