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Find the order and degree of differential equation : $e^{\Large\frac{d^6y}{dx^6}}-x^2 \large\frac{d^4y}{dx^4}$$+y=0$

$(a)\;6,1 \\ (b)\;6,2 \\ (c)\;4,2 \\ (d)\;6, not\; define $
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1 Answer

Expansion of $e^{\large\frac{d^6y}{dx^6}}$ contains higher power of $\large\frac{d^6y}{dx^6}$
So degree is not defined.
Hence d is the correct answer.
answered Feb 7, 2014 by meena.p

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