# Find the equation of normal for ellipse $\large\frac{x^2}{a^2}+\frac{y^2}{b^2}$$=1? \begin{array}{1 1}(a)\;\large\frac{a^2x}{x_1}+\frac{b^2y}{y_1}\normalsize= a^2-b^2\\(b)\;\large\frac{a^2x}{x_1}-\frac{b^2y}{y_1}\normalsize= a^2-b^2\\(c)\;\large\frac{a^2x}{x_1}+\frac{b^3y}{y_1}\normalsize =a^3-b^3\\(d)\;\text{None of these}\end{array} ## 1 Answer Comment A) We know slope of tangent at (x_1,y_1) is -\large\frac{x_1b^2}{a^2y_1} Slope of normal \large\frac{a^2y_1}{x_1b^2} Hence equation of normal is (y-y_1)=\large\frac{a^2y_1}{x_1b^2}$$(x-x_1)$
$\large\frac{y-y_1}{a^2y_1}=\frac{x}{x_1b^2}-\frac{1}{b^2}$
$\large\frac{y}{a^2y_1}-\frac{1}{a^2}=\frac{x}{x_1b^2}-\frac{1}{b^2}$
$\large\frac{a^2x}{x_1}-\frac{b^2y}{y_1}=$$a^2-b^2$