logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

Two concentric conducting spheres of radii R and 2R are carrying charges Q and -2Q respectively . If the charge on inner sphere is doubled the potential difference between the two spheres will becomes

$(a)\;two\;times\qquad(b)\;four\;times\qquad(c)\;be\;halved\qquad(d)\;remain\;same$

Can you answer this question?
 
 

1 Answer

0 votes
Answer : (a) two times
Explanation :
Initial potential difference between A & B
$V_{AB}=(\large\frac{kQ}{R}-\large\frac{k2Q}{2R})-(\large\frac{kQ}{2R}-\large\frac{k2Q}{2R})$
$V_{AB}=\large\frac{kQ}{2R}$
Final potential difference between A & B
$V^{|}_{AB}=(\large\frac{2kQ}{R}-\large\frac{2kQ}{2R})-(\large\frac{2kQ}{2R}-\large\frac{2kQ}{2R})$
$V^{|}_{AB}=\large\frac{kQ}{R}$
$V^{|}_{AB} = 2 V_{AB}\;.$
answered Feb 7, 2014 by yamini.v
edited Feb 7, 2014 by yamini.v
 

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...