Energy of electron in $n^{th}$ state
$= -\large\frac{Z^2}{n^2}\times$13.6eV
$E_2(H) = -\large\frac{13.6}{1}eV$
$E_3(He^+) = -\large\frac{13.6\times4}{9}eV$
$\large\frac{E_2}{E_3} = \large\frac{9}{4}$
$E_3 = \large\frac{4}{9}E_2$
For negative value of $E_2,E_3$ will also be negative.
Hence anwer is (c)