Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

Which of following satisfy the differential equation $y'+2xy=0?$

$(a)\;y=ce^{-x^2}, y'+2xy=0 \\ (b)\;y=x \log x-x,y'= \log x^2 \\ (c)\;y=\sin ^{-1}x, y''= \frac{x^2}{(1-x^2)^{3/2}}\\ (d)\;y=A e^{-1/x}, x^2y'-x-y=0 $

Can you answer this question?

1 Answer

0 votes
Check options and get answer like.
Substituting the values of $y\:and\:y'$ in the differential equation,
$\Rightarrow\:y'+2xy=-ce^{-x^2}.2x +2x ce^{-x^2}=0$
which satisfies the differential equation.
Hence (a ) is the correct answer.
answered Feb 7, 2014 by meena.p
edited Mar 13, 2014 by rvidyagovindarajan_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App