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If the electric potential of the inner shell is 10V and that of the outer shell is 5V , then the potential at the centre will be

$(a)\;10 V\qquad(b)\;5 V\qquad(c)\;15 V\qquad(d)\;zero$

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Answer : (a) 10V
Explanation :
Potential at surface of A =$\; \large\frac{k\;q_{1}}{a}+ \large\frac{k\;q_{2}}{2a}=10V$
Potential at centre = $\;\large\frac{k\;q_{1}}{a}+\large\frac{k\;q_{2}}{2a}$
$=10V\;.$
answered Feb 7, 2014 by yamini.v
edited Feb 7, 2014 by yamini.v
 

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