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A charged particle of mass m and charge q is released from rest from the position $\;(x_{0} ,0)\;$ in a uniform electric field $\;E_{0} \hat{j}\;.$ The angular momentum of particle about origin


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Answer : (c) increases with time
Explanation :
$=(x_{0} \hat{i}\times E_{0}\;q\;\hat{j})$
$\large\frac{d L}{dt}=E_{0}\;q\;x_{0}$
$\large\frac{d L}{dt}\;$ is positive i . e . L increases with time .
answered Feb 7, 2014 by yamini.v
edited Feb 7, 2014 by yamini.v

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