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Home  >>  JEEMAIN and NEET  >>  Physics  >>  Class12  >>  Current Electricity

A moving coil galvanometer of resistance $100 \Omega$ is used as an ammeter using a resistance of $ 0.1 \Omega$. The maximum deflection current in the galvanometer is $100 \mu A$. Find the current in the circuit so that the ammeter shows full scale deflection

$\begin {array} {1 1} (A)\;100.1 mA & \quad (B)\;1000.1mA \\ (C)\;10.01mA & \quad (dD\;1.01mA \end {array}$

 

1 Answer

The student is expected to know the working of an ammeter.
$i_gR_g = (i – i_g)R_s$
$i = (1 + \large\frac{R_g}{R_s}) $ $i_g$
On substituting the values, one gets $ i = 100.1mA.$
Ans : (A)
answered Feb 8, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1
 

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