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Resistance of a given wire is obtained by measuring the current flowing in it and the voltage difference applied across it. If the percentage errors in the measurement of the current and the voltage difference are 3% each, then error in the value of resistance of the wire is

$\begin {array} {1 1} (A)\;1 \% & \quad (B)\;2 \% \\ (C)\;3 \% & \quad (D)\;6 \% \end {array}$

$| \large\frac{ \Delta R}{R} | = | \large\frac{ \Delta V}{V} |+ | \large\frac{ \Delta i}{i} |$
On substituting in the above equation, the values of the parameters,
we get the error as 6%.
Ans : (D)
edited Mar 14, 2014