$\begin {array} {1 1} (A)\;\large\frac{R}{7} & \quad (B)\;\large\frac{6R}{7} \\ (C)\;\large\frac{5R}{6} & \quad (D)\;\large\frac{4R}{3} \end {array}$

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The question seems complicated but can be easily simplified if one keeps a track

of all the connections and identify the equipotential points.

Here 2, 4 and 5 are equipotential. Also 3, 6 and 8 are equipotential.

Representing the above points in a simple linear potential diagram results in the

following picture. Here, each connection corresponds to a resistance R

This is a very powerful technique. Student is expected to be thorough with its use.

Ans : (C)

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