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Home  >>  JEEMAIN and NEET  >>  Chemistry  >>  Atomic Structure

An oil drop has $-6.39\times10^{-19}$ coulomb charge .The number of electrons in this oil drop is

$(a)\;4\qquad(b)\;3\qquad(c)\;2\qquad(d)\;1$

1 Answer

Charge on one electron = $-1.60\times10^{-19}$
$\therefore$ The number of electron = $\large\frac{-6.39\times10^{19}}{-1.60\times10^{-19}}$
Thus the number of electron = 4
Hence answer is (a)
answered Feb 9, 2014 by sharmaaparna1
 

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