# A current of $1A$ is passing through $CuSO_4$ solution. How many $Cu^{+2}ions$ ions will be deposited at the cathode in 5 seconds?

$\begin {array} {1 1} (A)\;0.3 \times 10^{-19} & \quad (B)\;4 \times 10^{-19} \\ (C)\;15.625 \times 10^{-19} & \quad (D)\;1.5625 \times 10^{-19} \end {array}$

Numbers of ions are equal to the total charge passed through the
solution per unit charge on the ions
Ans : (D)
edited Mar 14, 2014