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Find the value of a,b whose foci are (6,4) and (-4,4) and ecentricity is 2?

$\begin{array}{1 1}(a)\;a=\large\frac{6}{7},\normalsize b=\large\frac{4\sqrt{3}}{5}\\(b)\;a=\large\frac{5}{2},\normalsize b=\large\frac{5\sqrt{3}}{2}\\(c)\;a=\large\frac{7}{5},\normalsize b=\large\frac{5\sqrt{7}}{2}\\(d)\;\text{None of these}\end{array}$

1 Answer

Distance between foci=2ae
$10=2\times a\times 2$
$b=\large\frac{5\sqrt 3}{2}$
Hence (b) is the correct answer.
answered Feb 10, 2014 by sreemathi.v

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