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# Find the position of the point (2,3) relative to the hyperbola $9x^2-y^2=1$?

$\begin{array}{1 1}(a)\;\text{inside the hyperbola}\\(b)\;\text{outside the hyperbola}\\(c)\;\text{centre of the hyperbola}\\(d)\;\text{none of these} \end{array}$

Since $9(2)^2-(3)^2-1=26 > 0$
So (2,3) inside the hyperbola $9x^2-y^2=1.$
Hence (a) is the correct answer.