$(a)\;63.3V\qquad(b)\;6.33V\qquad(c)\;633V\qquad(d)\;None \;of\; these$

$\lambda = \large\frac{h}{mu}$

$Q.V = \large\frac{1}{2}mu^2$

(where Q is the charge of electron)

$u = \sqrt{\large\frac{2.Q.V}{m}}$

$=\sqrt{\large\frac{2\times1.602\times10^{-19}}{9.108\times10^{-31}}}$

$=5.93\times10^5 \sqrt V$

$\lambda = \large\frac{6.626\times10^{-34}}{9.108\times10^{-31}\times5.93\times10^5\sqrt V}$

$\sqrt V = \large\frac{6.626\times10^{-34}}{9.108\times10^{-31}\times5.93\times10^5\times1.54\times10^{-10}}$

$\;\;\;\;\;\;\;\;\;=7.97$

$\therefore$ V = 63.3 V

Hence anwer is (a)

Ask Question

Tag:MathPhyChemBioOther

Take Test

...