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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class12  >>  Current Electricity
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An ammeter and a voltmeter are joined in series to a battery. Their readings are $A$ and $V$ respectively. If a resistance is now joined in parallel with the voltmeter

$\begin {array} {1 1} (A)\;Both\: A \: and\: V \: will \: increase & \quad (B)\;Both\: A \: and\: V\: will\: decrease \\ (C)\;A\: will\: decrease,\: V \:will\: increase & \quad (D)\;A \: will \: increase,\: V\: will\: decrease \end {array}$


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When a resistance is joined in parallel with a voltmeter, the net resistance of the circuit decreases,
hence the current increases.
The potential difference across the ammeter increases (due to more current) and hence,
potential difference across the voltmeter decreases (source EMF is constant).
Ans : (D)
answered Feb 10, 2014 by thanvigandhi_1
edited Mar 14, 2014 by thanvigandhi_1

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