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Current passing through the $1\: ohm$ resistor is zero. The value of $E$ is

$\begin {array} {1 1} (A)\;2V & \quad (B)\;4V \\ (C)\;6V & \quad (D)\;8V \end {array}$

Ans : Since no current passes through the 1 ohm resistor the potential drop across its terminal must be zero.
Thus to balance the 6V battery the value of E must be 6V
(C)

edited Sep 10, 2014