$(a)\;1s\qquad(b)\;2s\qquad(c)\;2p\qquad(d)\;3s$

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For $S_1$ (spherically symmetrical) state, number of nodes = 1

1 = n-1

$\therefore$ n = 2

i.e it is 2s

For $S_2$ radial node = 1

$E_{s_2} = \large\frac{-13.6\times z^2}{n^2} = E_H$ in ground state

= -13.6

$E = \large\frac{-13.6\times9}{n^2}$

$\Rightarrow n = 3$

So state is $S_1$ is 2s and $S_2$ is 3p

Hence answer is (b)

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