Browse Questions

# Minimum size of plane mirror, required to see full image of an observer is :

(a)double size of that observes

(b) same size as that of observer

(c)half size of that observer

(d)None

In that diagram $H'$-head
$F'=$ feet\Delta EM_1M_2$and$ \Delta E H' F' $are similar$\therefore \large\frac{M_1M_2}{H'F]}=\frac{Z}{2Z}$pr$M_1M_2=H' \large\frac{F'}{2}\qquad=\large\frac{HF}{2}\$
Hence c is the correct answer.