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Minimum size of plane mirror, required to see full image of an observer is :

(a)double size of that observes

(b) same size as that of observer

(c)half size of that observer  

(d)None 

Can you answer this question?
 
 

1 Answer

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In that diagram $H'$-head
$F'= $ feet$
$\Delta EM_1M_2$ and $ \Delta E H' F' $ are similar
$\therefore \large\frac{M_1M_2}{H'F]}=\frac{Z}{2Z}$
pr $M_1M_2=H' \large\frac{F'}{2}$
$\qquad=\large\frac{HF}{2}$
Hence c is the correct answer.
answered Feb 10, 2014 by meena.p
 

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